Help please! I need to write 4y =-3x + 12 in standard form, find the y-intercept of the previous equation, as an ordered pair, and find the x-intercept of the previous equation, but I forgot how. I need the answer asap! Thank you!
Accepted Solution
A:
Answer:[tex]-3x+4y=12\\y-intercept: (0,3)\\x-intercept: (-4,0)[/tex]Step-by-step explanation:The standard form of a linear equation is [tex]ax+by=c[/tex], where [tex]a[/tex] , [tex]b[/tex], and [tex]c[/tex] are constants in the equation.Based on the equation you have provided, the standard form would be [tex]-3x+4y=12[/tex], where [tex]a=-3, b=4, c=12[/tex].To find the y-intercept, set [tex]x=0[/tex].[tex]-3(0)+4y=12\\0+4y=12\\4y=12\\y=\frac{12}{4} =3[/tex]Therefore, the y-intercept is [tex](0,3)[/tex].Do the same thing for the x-intercept, but this time with [tex]y=0[/tex].[tex]-3x+4(0)=12\\-3x+0=12\\-3x=12\\x=\frac{12}{-3} =-4[/tex]Therefore, the x-intercept is [tex](-4,0)[/tex].