PLEASE HELP!A solid object is dropped into a pond with a temperature of 20°C. The function f(t)=Ce^(-my)+20 represents the situation, where T is times in minutes, C is a constant in K= 0.0399. After four minutes the object has a temperature of 35°C what was the initial temperature of the object round your answer to the nearest tenth, and do not include units

Answer:The initial temperature of the object was 37.6Step-by-step explanation:we have[tex]f(t)=Ce^{(-kt)} +20[/tex]wheref(t) represent the temperature of the object in degree Celsiust is the time in minutesFind the value of the constant Cwe have the ordered pair (4,35)substitute in the equation and solve for C[tex]35=Ce^{(-0.0399*4)} +20\\Ce^{(-0.0399*4)}=15\\C=15/e^{(-0.0399*4)}\\C=17.6[/tex]Find the initial value of the objectwe know thatThe initial temperature is the value of f(t) when the value of t is equal to zerosoFor t=0[tex]f(0)=(17.6)e^{(-k*0)} +20\\f(0)=17.6 +20\\f(0)=37.6[/tex]thereforeThe initial temperature of the object was 37.6 (I not include units)